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in Arithmetic Progression by (44.9k points)
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Sum of the first 14 terms of an AP is 1505 and its first term is 10. Find is 25th term.

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Correct Answer - `T_(25) = 130`
`(n)/(2)(a+l) = 1505 rArr (14)/(2) (10+l) = 1505 rArr l = 205.`
`T_(14) = 205 rArr a +13d = 205 rArr 10+13d = 205 rArr d = 15`
`T_(25) = (a+24d) = (10+24 xx 5) = 130`

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