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सिद्ध कीजिए कि:`(sin2theta+sintheta)/(cos2theta+costheta+1)=tantheta.`

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बायाँ पक्ष `(sin2theta+sintheta)/(cos2theta+costheta+1)=(2sinthetacostheta+sintheta)/(2cos^(2)theta-1+costheta+1)`
`=(sintheta(2costheta+1))/(2cos^(2)theta+costheta)=(sintheta(2costheta+1))/(costheta(2costheta+1))=(sintheta)/(costheta)=tan theta=`दायाँ पक्ष।

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