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The valence electronic configuration of an atom is `6s^2` If d-orbital of the penultimate shell contains two unpaired electrons, calculate the atomic number

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Since the valence electronic configuration of the atom is `6s^2` and cl-orbital of the penultinute shell contains two unpaired electrons, the electromc configuration is `[Xe]6s^24f^(14)5d^2`Therefore, the atomic number of the elen1ent is 72.

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