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Prove that `cos^2 theta cosec^2 theta+sin^2 theta=cosec^@ theta`

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L.H.S. `=cos^(2)theta*cosectheta +sin theta = cos^(2)theta*(1)/(sintheta)+sintheta`
`=(cos^(2)theta)/(sintheta)+(sintheta)/(1)=(cos^(2)theta+sin^(2)theta)/(sintheta)=(1)/(sintheta)`
`=cosectheta = R.H.S.`

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