Correct Answer - In the diagram, show a parallel combination of two resistors `2 Omega` each and this combination in series with one resistors of `2 Omega`.
The resultant of parallel combination of two resistors (each of `2 Omega`) is `1 Omega`. When this combination is connected in series with the third resistor of `2 Omega`, the resultant resistance `= 1 Omega + 2 Omega = 3 Omega`.