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An electric heater a current of `5 A` and its element has a resistance of `50 Omega`. If the heater is switched on for `5` minutes, calculate the energy released in kilojoules.

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Correct Answer - 375 kJ
`W = I^2 Rt = (5 A)^2 (50 Omega)(5 xx 60 s) = 375000 J = 375 kJ`.

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