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An object is placed at a distance of `10 cm` from a convex mirror of focal length `15 cm`. Find the position and nature of the image ?

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Here, object distance, `u = -10 cm`, focal length, `f = 15 cm`, image distance, `v = ?`
As `(1)/(v) + 1/u = (1)/(f), (1)/(v) = (1)/(f) - 1/u = 1/15 + 1/10 = (2 + 3)/30 = 5/30 = 1/6 or v = 6 cm`
Here, `+` sign of v indicates that image is at the back of the mirror. It must be virtual, erect and smaller in size than the object.

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