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in Second Degree Equations by (30.9k points)
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For a two-digit number, one’s place is 3 more than its ten’s place. The product of this number and its digit sum is square of double the digit sum. What is the number?

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Best answer

Digits: x, x+3

Number: 10x + x + 3 = 11x + 3

Product of the number and digit sum: (2x + 3)

(11x + 3) = (4x + 6)2

22x2 + 39x + 9 = 16x2 + 48x + 36

6x2 - 9x - 27 = 0,

2x2 - 3x - 9 = 0

(-ve being a fraction not acceptable)

Number = 36

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