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If m sin θ = n sin (θ + 2α), then prove that tan (θ + α) cot α = (m+n)/(m-n)

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If m sin θ = n sin (θ + 2α), then prove that tan (θ + α) cot α = (m+n)/(m-n)

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We have, m sin θ = n sin (θ + 2α)

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