Correct Answer - a
We have
`(1 + x)^(59) = sum_(r = 0)^(29) ""^(59)C_(r) x^(r)`
`rArr 2^(59)= sum_(r = 0)^(29) ""^(59)C_(r)` [Putting x = 1]
`rArr 2^(59)= 2(sum_(r = 0)^(29) ""^(59)C_(r)) (because ""^(59)C_(r)= ""^(59)C_(59-r), r = 0,1,...29]`
`rArr 2^(58)= sum_(r = 0)^(29) ""^(59)C_(r)`
`rArr 2^(58)= sum_(r = 0)^(29) ""^(59)C_(59-r = 2^(58))` .