Correct Answer - c
The given expansion can be written as
`ubrace ({( 1+ x) (1 + x) (1 + x)...(1 +x)})_("n - factors") ubrace({( 1 +y)(1 +y) (1 +y)...(1 +y)})_("n - factors")`
`ubrace({( 1 +z)(1 +z) (1 +z)...(1 +z)})_("n - factors")`
There are 3n factors in this product .
To get a term of degree r. we choose r factors out of these 3n
factors and then multiply second terms in each factor. there
are `""^(3n)C_(r)` such terms each having coefficient 1.
Hence, the sum of the coefficients of `""^(3n)C_(r)`.