The given equations are:
`x-y-6=0........(i)`
`4x-3y-20=0.....(ii)`
`6x+5y+8=0.......(iii)`
On solving (i) and (ii) by cross multiplication, we get
`(x)/((20-18))=(y)/((-24+20))=(1)/((-3+4)) Rightarrow (x)/(2)=(y)/(-4)=(1)/(1) Rightarrow x=2, y=-4`
Thus, the line (i) and (ii) intersect at the point P(2,-4)
Putting x=2 and y=-4 in (iii), we get
`LHS=6xx2+5xx(-4)+8=0=RHS`
This shows that the point P(2,-4) also lies on (iii), Thus, all the given three lines intersect at the same point.
Hence, the given line are concurrent and their point of intersection is P(2,-4).
