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Find the equation of a line which cuts off intercept 5 on the x-axis and makes an angle of `60^(@)` with the positive direction of the x-axis.

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Find the equation of a line which cuts off intercept 5 on the x-axis and makes an angle of `60^(@)` with the positive direction of the x-axis.
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Correct Answer - `sqrt3x-y-5sqrt3=0`
The given line passes through the point (5,0) and `m=tan 60^(@)=sqrt3`. So, the required equation is `(y-0)/(x-5)=sqrt3 Leftrightarrow y=sqrt3(x-5)`.
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