Question

A man saves ₹ 4000 during first, year, ₹ 5000 during second year and in this way he increaes his savings by ₹ 1000 every year. Find in what time his savings will be ₹ 85000.

Answer 1

Correct Answer - 10 years
Let the total savings be ₹ 8500 in years.Then,
` n/2 xx[2xx 4000 + (n-1) xx 1000 ] = 85000`
` n^(2)+7n -170 =0 Rightarrow ( n +17) (n-10) =0 Rightarrow n= 10 ` years.