Angle of the right 45°, 45°, 90°
Ratio of sides = 1 : 1 : √2
hypotenuse = 20cm
∴ The other two sides are \(\frac{20}{\sqrt{2}}\) cm each
∴ Area of the right angled triangle = \(\frac{1}{2}\times\frac{20}{\sqrt{2}}\times\frac{20}{\sqrt{2}}\) = \(\frac{1}{2}\times\frac{20\times20}{2}=100\) cm2
