Use app×
QUIZARD
QUIZARD
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
164 views
in Straight Lines by (71.2k points)
closed by
Find the equations of the line which passes through the point `(3,4)` and the sum of its intercepts on the axes is`14` .

1 Answer

0 votes
by (70.6k points)
selected by
 
Best answer
Let the intercepts made by the line on the x-axis and y-axis be a and (14-a) respectively.
Then, its equation is `(x)/(a)+(y)/((14-a))=1" "["intercept form"]`
Since it passes through the point (3,4), we have
`(3)/(a)+(4)/((14-a))=1 Leftrightarrow 3(14-a)+4a=a(14-a)`
`Leftrightarrow a^(2)-13a+42=0 Leftrightarrow (a-6)(a-7)=0`
`Leftrightarrow a=6 or a=7`
`"Now," a=b Leftrightarrow 14-6=8`
`"And" a=7 Leftrightarrow 14-7=7`
So, the required equation is
`(x)/(6)+(y)/(8)=1 or (x)/(7)+(y)/(7)=1`
`i.e. 4x+3y-24=0 or x+y-7=0`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...