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The locus of the point of intersection of the tangents to the parabola `y^2 = 4ax` which include an angle `alpha` is
A. `(x+a)^(2)tan^(2)alpha=y^(2)-4ax`
B. `(x+a)tan^(2)alpha=y^(2)-4ax`
C. `(x-a)^(2)tan^(2)alpha=y^(2)-4ax`
D. none of these

1 Answer

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Best answer
Correct Answer - A
Let P(h, k) be the point of intersection of tangents to the parabola `y^(2)=4ax` is
`y=mh+a/m`
If it passes through (h, k), then
`k=mh+1/mrArrm^(2)h-mh+a=0`
Let `m_(1), m_(2)` be the roots of this equation. Then,
`m_(1)+m_(2)=k/h" and "m_(1)m_(2)=a/h`
Clearly, `m_(1), m_(2)` are the slopes of the tangents drawn from P.
`:." "tanalpha=(m_(1)-m_(2))/(1+m_(1)m_(2))=(sqrt((m_(1)+m_(2))^(2)-4m_(1)m_(2)))/(1+m_(1)m_(2))`
`rArr" "tanalpha(sqrt(k^(2)-4ah))/(a+h)rArrk^(2)-4ah=(a+h)^(2)tan^(2)alpha`
Hence, the locus of (h, k) is `y^(2)-4ax=(a+x)^(2)tan^(2)alpha`

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