Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
69 views
in Ellipse by (71.2k points)
closed by
The length of the major axis of an ellipse is 20 units and its foci are `(pm 5sqrt3, 0).`
Find the equation of the ellipse.

1 Answer

0 votes
by (70.6k points)
selected by
 
Best answer
Correct Answer - `x^(2)/100+y^(2)/25 = 1`
Let the equation of the ellipse be `x^(2)/a^(2) + y^(2)/b^(2) = 1.`
Length of the major axis = ` 20 hArr 2a = 20 hArr a = 10.`
Foci are `(pm c, 0) rArr c = 5 sqrt 3.`
Now, ` c^(2) = (a^(2)-b^(2)) hArr b^(2) = (a^(2)-c^(2)) = (100-75) = 25.`
`:. ` the required equation is `x^(2)/100+ y^(2)/25 = 1.`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...