Use app×
QUIZARD
QUIZARD
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
179 views
in Mathematics by (69.1k points)
closed by
If the eccentricity of an ellipse is `5/8` and the distance between its foci is `10 ,` then find the latusrectum of the ellipse.

1 Answer

0 votes
by (67.8k points)
selected by
 
Best answer
Given that, eccentricity=`5/8i.e.,e=5/8`
Let equation of the ellipse be `(x^(2))/(a^(2))+(y^(2))/(b^(2))=1` ltvbrgt since the foci of the ellipse is `)pmae,o)`.
`therefore` Distance between foci =`sqrt((ae+ae)^(2))`
`rArr 2sqrt(a^(2)e^(2))=10` [`because` distance between the foci=10]
`rArr sqrt(a^(2)e^(2))=5`
`rArr a^(2)e^(2)=25`
`rArr a^(2)=(25xx64)/25`
`thereforea=8`
We know that,
`rArr b^(2)=a^(2)(1-e^(2))`
`rArr b^(2)=64(1-25/64)`
`rArr b^(2)=64((64-25)/64)`
`b^(2)=39`
`therefore` Length of latusrectum of ellipse=`(2b^(2))/a=2(39/8)=39/4`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...