Correct Answer - B
The line 3x + 2y = 24 meets the coordinate axes at A (8,0) , B( 0 , 12) . The coordinates of the mid-point D of AB are (4,6) . Equation of the perpendicular bisector of AB is 2x - 3y + 10 = 0
This meets the line through (0 ,-1) parallel to the x-axis i.e.
y = -1 at C (-13/2 , -1) .
`therefore` Area of `DeltaABC = (1)/(2) AB xx CD`
`implies` Area of `Delta ABC = (1)/(2) sqrt(64 + 144) xx sqrt(((13)/(2) + 4)^(2) + (1-6)^(2))`
`implies` Area of `Delta ABC = (1)/(2) xx sqrt(208) xx 7 sqrt((9)/(4) + 1) = 91` sq. units
So , statement-1 is true .
The area of the triangle with vertices at (a,0) , (0, b) and (a , b) is
Absolute value of `(1)/(2) |{:(a , b , 1), (0 , b , 1) , (a , b , 1):}| = (1)/(2)` ab sq. units .
So , statement - 2 is true . But , statement - 2 is not a correct explanation for statement - 1 .