Correct Answer - C

Let a be the term and d be the common difference of the given AP. Then,

`T_(m)=(1)/(n)rArra=(m+1)d=(1)/(n)` . . . (i)

`and,T_(n)=(1)/(m)rArra+(n-1)d=(1)/(m)` . . . (ii)

Solving (i) and (ii), we get `d=(1)/(mn)anda=(1)/(mn)`

`:." "T_(mn)=a+(mn-1)d=(1)/(mn-1)(1)/(mn)=1`