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The number of porper divisors of `2^(m)xx6^(n)xx15^(p)` , is

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The number of porper divisors of `2^(m)xx6^(n)xx15^(p)` , is
A. `(m+n+1)(n+p+1)(p+1)`
B. `(m+n+1)(n+p+1)(p+1)-2`
C. `(m+n)(n+p)-2`
D. none of these
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We have, `2^(m)xx6^(n)xx15^(p)=2^(m+n)xx3^(n+p)xx5^(p)`
Hence, total number of proper divisors
`=(m+n+1)(n+p+1)(p+1)-2`.
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