Let C be the set of students who play cricket and T be the set of students who play tennis.
Then, `n (U) = 60, n (C ) = 25, n(T) = 20` and `n(C nn T) = 10`
`:. N(C uu T) = n(C ) + n (T) - n (C nn T)`
`= 25+ 20 - 10 = 35`
`:.` Number of students who play neither `= n(U) - n(C uu T)`
`= 60 - 35 = 25`