∆ OMP is a right triangle
\(\therefore \,OP=\sqrt{48^2+36^2}=60\)
∆ PAO, ∆ OMP are similar
= \(\frac{OA}{OP}=\frac{OP}{PM}\)
\(\therefore\,OA=\frac{OP^2}{PM}=\frac{60^2}{48}=75\)
∆ OMP, ∆ OPB are similar.
= \(\frac{OB}{OP}=\frac{OP}{OM}\)
\(\therefore \,OB=\frac{OP^2}{OM}=\frac{60^2}{36}=100\)
Coordinates of M (36, 0)
Coordinates of A (0, 75)
Coordinates of B (100, 0)