\(\because \) OP makes 60° angle with positive direction of x-axis and OP = r = 2
\(\therefore\) Coordinates of point P are (rcos60°, rsin60°)
\(= (2 \times \frac 12, 2\times \frac {\sqrt 3}2)\)
\(= (1, \sqrt 3)\)
Similarly, OQ makes (60° + 90° = 150°) angle with +ve direction of x-axis
\(\therefore\) Coordinates of point Q are (rcos150°, rsin150°)
\(= (2\times \frac {-\sqrt 3}2,2 \times \frac 12 )\)
\(= (-\sqrt 3,1)\)
Hence, coordinates of P are (1, √3) & coordinates of Q are (-√3, 1).
