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JEE MAIN 2026 Crash Course
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प्रश्न से `3cot^(2) theta -1=0` या `cot^(2) theta =(1)/(2)`
या `cot theta =pm(1)/(sqrt(3))` या `tan theta =pm sqrt(3)`
जब `tan theta =-sqrt(3)`, तो `tan theta = "tan" (pi)/(3)`
`:. theta=n pi+(pi)/(3), n iin Z" "....(1)`
जब `tan theta =sqrt(3)` तो `tan theta =tan (-(pi)/(3))`
`:. theta=npi-(pi)/(2), n in Z " "...(2)`
(i) और (2) से `theta= n pi pm(pi)/(3), n in Z`.

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