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in Continuity and Differentiability by (31.4k points)
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If f is continuous at x = 0 and

\(f(x) = 2\sqrt{x^3 + 1} + a,\) for x < 0

f(x) = 2(√x3 + 1) + a, for x < 0

= x3 + a + b, for x ≥ 0

and f(1) = 2, then find a, b.

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by (35.1k points)
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Best answer

f(x) = 2(√x3 + 1) + a

Given, f is continuous at x = 0

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