Question

How many GAMs are present in each the samples given below? Calculate the, number of atoms present in each of die sample ? (Atomic mass N= 14, O= 16) 

1. 42g Nitrogen, 

2. 80g Oxygen

Answer 1

1. 42g Nitrogen:

No.of GAM = \(\frac{42}{14}\) = 3 GAM

No.of atoms = 3 x 6.022 x 10²³

2. 80g Oxygen:

No.of GAM = \(\frac{80}{16}\) = 5GAM

No.of atoms = 5 x 6.022 x 10²³