Question

If x³+ x² -ax + b is divisible by (x² -x),write the value of a and b.

Answer 1

Equating x² – x to 0 to find the zeroes, we will get 

x(x – 1) = 0 

⇒ x = 0 or x – 1 = 0 

⇒ x = 0 or x = 1 

Since, x³ + x² – ax + b is divisible by x² – x. 

Hence, the zeroes of x² – x will satisfy x³ + x² – ax + b 

∴ (0)³ + 0² – a(0) + b = 0 

⇒ b = 0 

And (1)³ + 1² – a(1) + 0 = 0 [∵b = 0] 

⇒ a = 2 

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