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An electric iron is rated at 230 V, 750 W. Calculate (i) the maximum current, and (ii) the number of units of electricity it would use in 30 minutes.

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V=230V, P=750 W, t=30/60=0.5hr 

(i) Let max current be I 

We have P=VI 

750 =230xI 

I= 3.26 A 

(ii) Electric energy consumed, E = Pxt = 0.75kW x 0.5h = 0.375 kWh 

No. of units used in 30 min = 0.375

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