Question

A 0.20 Kg aluminum block at 80⁰C is dropped in a copper calorimeter of mass 0.05 Kg containing 200 cm³ of ethyl alcohol at 20⁰C. What is the final temperature of the mixture? Given Density of ethyl alcohol = 0.81 g | cm³ ; specific heat of ethyl alcohol = 0.6 cal | g | ⁰C ; specific heat of copper = 0.094 cal | g | ⁰C, specific heat of Al = 0.22 cal | g | ⁰C?  

Answer 1

Let θ⁰C = final temperature of the mixture.

 Mass of ethyl alcohol = volume ×Density

= 200 × 0.81

Heat lost by Aluminum block = Mass X specific heat X fall in temperature

Heat gained by the ethyl alcohol and calorimeter = (Mass of ethyl alcohol × specific heat × change in Temperature) + Mass of copper calorimeter × specific heat X change in Temperature