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0 votes
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in Chemistry by (62.3k points)
During ionisation of copper atom, the quantum numbers of electron removed maybe
A. `n = 4 l = 1 s= +(1)/(2)`
B. `n = 3 l = 0 s =- (1)/(2)`
C. `n = 4 l = 0 s = +(1)/(2)`
D. `n = 4 l = 2 s =- (1)/(2)`

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1 Answer

0 votes
by (58.9k points)
Correct Answer - C
`e^(-)` removed from 4s orbital

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