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Calculate the wave number for the shortest wavelength transition in the Balmer series of atomic hydrogen.

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Calculate the wave number for the shortest wavelength transition in the Balmer series of atomic hydrogen.
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For shortest wavelenght `n_(2)rarroo`
` barV=R[(1)/2^(2)-(1)/oo^(2)]`=`(R)/(4)`=`27419.25cm^(-1)`
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