Question

The Wave function (Psi) of 2s is given by:
`Psi_(2s)=(1)/(2sqrt2pi)(1/a_(0))^(1//2){2-(r)/a^(0)}e^(-r//2a_(0))`
At `r =r_(0)`, radial node is formed . Thus for 2s `,r_(0),` in terms of `a_(0)` is-
A. `r_(0)=a_(0)`
B. `r_(0)=2a_(0)`
C. `r_(0)=a_(0)//2`
D. `r_(0)=4a_(0)`

Answer 1

Correct Answer - B
Where `r=r_(0)`,`Psi2_(s)=0`, then from the given equation :
`2-(r)/(a_(0))=0`
`r=2a_(0)`