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`0.24eV` of energy is required to stop photoelectron emitted by radiation of wavelength `2480 Å`. Find work function of metal used?

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`0.24eV` of energy is required to stop photoelectron emitted by radiation of wavelength `2480 Å`. Find work function of metal used?
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Let `phi eV` =work funcion
`K.E =0.24 eV =(1240)/(248)-phiimpliesphi=4.76 eV`
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