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The orbital angular momentum of an electron in `2s`-orbital is

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The orbital angular momentum of an electron in `2s`-orbital is
A. `+1/2. h/(2pi)`
B. Zero
C. `h/(2pi)`
D. `sqrt2. h/(2pi)`
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1 Answer

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Correct Answer - B
The expression of orbital angular momentum is `L=sqrt(l(1+1)(h//2pi))`
For 2s orbital , l=0 , Hence , l=0
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