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The resistance of a 10cm long wire is 120. If this is folded into two parts of equal length and included in a circuit, how much will be the resistance produced?

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When folded into two parts, length is halved and area of cross-section is doubled. Due to the decrease in length, resistance is halved. Also due to the decrease in area of cross section, resistance is again halved.

So effective resistance R = \(12\times\frac{1}{2}\times\frac{1}{2}=3\Omega\)

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