Use app×
QUIZARD
QUIZARD
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
195 views
in Chemistry by (63.2k points)
closed by
`1.50` moles each of hydrogen and iodine is p[laced in a sealed 10 litre container maintained at 717 K. At equilibrium `1.25` moles each of hydrogen and iodine were left behind. The equilibrium constant `K_(c)` for the reaction `H_(2)(g) + I_(2)(g)hArr2HI(g) at 717` K is
A. `0.4`
B. `0.16`
C. 25
D. 50

1 Answer

0 votes
by (67.2k points)
selected by
 
Best answer
Correct Answer - B
`H_(2)(g) + I_(2)(g)hArr2HI(g)`
`t = 0` `1.5` `1.5` 0
`t = t_(equiv)` `1.5-x` `1.5-x` 2x
We, know, `1.5-x = 1.23`, or `x = .25`
`K_(c) = ((.5)^(2))/((1.25)^(2)) = 0.16`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...