Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
56 views
in Chemistry by (63.2k points)
closed by
Two equilibrium `ABhArrA^(o+)+B^(Θ)` and `AB+B^(Θ)hArrAB_(2)^(Θ)` are simultaneously maintained in a solution with equilibrium constants `K_(1)` and `k_(2)`, respectively. Ratio of `[A^(o+)]` to `[AB_(2)^(Θ)]` in the solution is
A. Direclty proportional to `[B^(ɵ)]`
B. Inversely proportional to `[B^(ɵ)]`
C. Directly proportional to `[B^(ɵ)]^(2)`
D. Inversely proportional to `[B^(ɵ)]^(2)`

1 Answer

0 votes
by (67.2k points)
selected by
 
Best answer
Correct Answer - D
`K_(1)=([AB^(o+)][B^(ɵ)])/([AB]), K_(2)=[AB_(2)^(ɵ)]//[AB][B^(ɵ)]`
or `[A^(o+)]=(K_(1)[AB])/([B^(ɵ)]),[AB_(2)^(ɵ)]=(K_(2)[AB][B^(ɵ)])/([AB_(2)^(ɵ)])`
`:.([A^(o+)])/([AB_(2)^(ɵ)]) prop1/([B^(ɵ)]^(2))`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...