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In the following unbalanced redox reaction,
`Cu_(3)P+Cr_(2)O_(7)^(2-) rarr Cu^(2+)+H_(3)PO_(4)+Cr^(3+)`
Equivalent weight of `H_(3)PO_(4)` is
A. `(M)/(3)`
B. `(M)/(6)`
C. `(M)/(7)`
D. `(M)/(8)`

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Best answer
Correct Answer - D
`underset(+5)underset(uarr)(Cu_(3)P) rarr underset(+5)underset(uarr)(H_(3)PO_(4))`
Change in oxidation number `=8` units of phosphorus
`:. ` Equivalent weight of `H_(3)PO_(4)=(M)/(8)`

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