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Mole fraction of a solute in an aqueous solution is 0.2. The molality of the solution will be
A. 13.88
B. 1.388
C. 0.138
D. 0.0138

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Correct Answer - A
`chi_(B) = 0.2. chi_(A) = 0.1`
`m = (chi_(B) xx 1000)/(chi_(A) xx Mw_(A)) = (0.2 xx 1000)/(0.8 xx 18) = 13.88`

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