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Calculated the molality of a sulphuric acid solution in which the mole fraction of water is 0.85.

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Calculated the molality of a sulphuric acid solution in which the mole fraction of water is 0.85.
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`m = (X_(2) xx 1000)/(X_(1) xx Mw_(1))` ltbgt `X_(1) = 0.85, X_(2) = 1 - 0.85 = 0.15`
`m = (0.15 xx 1000)/(0.85 xx 18) = 9.8`
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