Autoprotolysis of `H_(2)O` takes place as :
`{:(H_(2)O+H_(2)O,hArr,H_(3)O^(+)+OH^(-)),(" "H_(2)O,hArr,H^(+)+OH^(-)):}`
For ionization of `H_(2)O`,
`K_(i)=([H^(+)][OH^(-)])/([H_(2)O])=(K_(w))/([H_(2)O])=(K_(w))/(55.55 "mol" L^(-1)) or K_(w)=K_(i)xx55.55`.