Use app×
QUIZARD
QUIZARD
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
125 views
in Chemistry by (74.1k points)
closed by
Describe the hydribisation in case of `PCl_(5)`. Why are the axial bonds longer as compared to equatorial bonds?

1 Answer

0 votes
by (73.8k points)
selected by
 
Best answer
The ground state and excited state outer electronic configuration of phosphorus (Z=15) are :
Ground state :
image
Excited state:
image
Phosphorus atom is `sp^(3)d` hybridized in the excited state. These orbitals are filled by the electron pairs donated by five Cl atoms as :
`PCl_(5)`
image
The five `sp^(3)d` hybrid orbitals are directed towards the five corners of the trigonal bypyramidals. Hence, the geometry of `PCl_(5)` can be represented as:
image
There are five P-Cl sigma bonds is `PCl_(5)`. Three P-Cl bonds lie in one plane and make an angle of `120^(@)` with each other. These bonds are called equatorial bonds.
The remaining two P-Cl bond lie above and below the equatorial plane and make an angle of `90^(@)` with the plane. These bonds are called axial bonds.
As the axial bond pairs suffer more repulsion from the equatorial bond pairs, axial bonds are slightly longer than equatorial bonds.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...