Correct Answer - C
c) The electrons configuration of the given molecules, are
`N_(2)^(+)= sigma1s^(2), sigma^(star)1s^(2), sigma2s^(2), sigma^(star)2s^(2), pi2p_(x)^(2)=pip_(y)^(2), sigma2p_(z)^(1)`
It has one unpaired electron, `O_(2)= sigma1s^(2), sigma^(star)1s^(2), sigma2s^(2), sigma^(star)2s^(2), pi2p_(x)^(2)=pip_(y)^(2),pi^(star)2p_(x)^(1)~~pi^(star)2p_(y)^(1)`
`O_(2)` has two unpaired electrons.
`O_(2)^(-) = sigma1s^(2), sigma^(star)1s^(2), sigma2s^(2), sigma^(star)2s^(2), pi2p_(x)^(2)=pip_(y)^(2),pi^(star)2p_(x)^(2)~~pi^(star)2p_(y)^(2)`
Thus, `O_(2)^(2-)` has no unpaired electrons.
`B_(2) = sigma1s^(2), sigma^(star)1s^(2), sigma2s^(2), sigma^(star)2s^(2), pi2p_(x)^(1)=pip_(y)^(1)`
Thus, `B_(2)` has two unpaired electrons.
