Correct Answer - b
(i) Hybridization of `NH_(3) (sigma =- 3, lp = 1)`
(ii) Structure of `XeF_(4)` is square planner.
structure of `XeO_(4)` is tetrahedral
So `XeF_(4)` and `XeO_(4)` are not isostructural
(iii) Structure of `SiCl_(4)` is tetrahedral
Structure of `PCl_(4)^(+)` is tetrahedral
(vi) Both diamond and SiC are isostrucitral because both have terabdral arrangement and atom is `sp^(2)` hybridization