Question

ABC is an isosceles triangle, right-angled at B. Similar triangles ACD and ABE are constructed on sides AC and AB. Find the ratio between the areas of ∆ABE and ∆ACD.

Answer 1

We have, ABC as an isosceles triangle, right angled at B. Now, AB = BC 

Applying Pythagoras theorem in right-angled triangle ABC, we get:

We know that ratio of areas of 2 similar triangles is equal to squares of the ratio of their corresponding sides.