Question

The dipole moment of `HBr` is ` 1.6 xx 10^(-30) cm` and interatomic spacing is `1 Å`. The `%` ionic character of `HBr` is
A. 7
B. 10
C. 15
D. 27

Answer 1

Correct Answer - b
Charge of `e^(-) = 1.6 xx 10^(-19)`
Dipole moment of `HBr = 1.6 xx 10^(-30)`
Inter atomic specing `= 1 Å = 1 xx 10^(-10) m`
`%` of ionic charcter in
`HBr = ("dipole moment of HBr" xx 100)/("inter spacing distance" xx q)`
`= (1.6 xx 10^(-30))/(1.6 xx 10^(19) xx 10^(-10)) xx 100`
`= 10^(-30) xx 10^(29) xx 100 xx 10^(-1) xx 100`
`= 0.1 xx 100 = 10%`