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Give reasons for the following : `CH_2=CH^-` is more basic than `HC-=C^-`

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`CH_2=CH^-` is the conjugate base of the acid `H_2C=CH_2` and `HC-=C^-` is the conjugate base of the acid `HC-=CH` . We know that stronger the acid , weaker is the conjugate base. Since , `HC-=CH` is a stronger acid than `CH_2=CH_2` , therefore , `CH_2=CH^-` is a stronger base than `HC-=C^-`

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