i. One side of a square is 3 cm, therefore its diagonal is 3√2 cm Diameter of the circle = 3√2 cm
ii. Rectangle inside the circle having length 4 cm and breadth 2 cm.
Diagonal = \(\sqrt{4^2+2^2}=\sqrt{16+4}\)
\(=\sqrt{20}\) cm
Diameter of the circle = √20 cm
Radius = \(\frac{\sqrt{20}}{2}\)cm
Area = \(\pi\times(\frac{\sqrt{20}}{2})^2=\pi\times\frac{20}{4}\)
= 5 π cm2